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6 answers

It only has two elements.
{-sqrt(3), sqrt(3)}

2006-06-07 20:49:28 · answer #1 · answered by MsMath 7 · 7 0

x^2=3
Solve this equation.
Take square roots of both sides of this equation.
x1=-sqrt(3)
x2=+sqrt(3)
Write these values in a set.

2006-06-07 23:45:51 · answer #2 · answered by iyiogrenci 6 · 0 0

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2016-11-14 08:32:34 · answer #3 · answered by ? 4 · 0 0

I concur with mathgirl826

x^2 = 3

x = - sq rt of 3 and x = + sq rt of 3

2006-06-07 21:11:44 · answer #4 · answered by dax 3 · 0 0

i re-iterate..... the set has only two elements- sqrt(3) and -sqrt(3)

2006-06-07 23:12:56 · answer #5 · answered by neo_kryptik 1 · 0 0

I don't really understand your point, but isn't it just a simple {9} ???

2006-06-07 20:19:18 · answer #6 · answered by Mighty Martin 2 · 0 0

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