At about 32 feet per second per second.
That means for every second an object falls, it will accelerate 32 feet per second.
2006-06-07 19:06:03
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answer #1
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answered by Eric 2
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Apply newtons law of universal gravitation and his 2nd law:
F = GMm/r^2
F = ma = GMm/r^2
a = GM/r^2
Where:
a = acceleration
G = universal gravitational constant, 6.6742 x 10^-11 m3/ kg-s^2
M = mass of the earth,5.98 x 10^24 kg
r = distance of the object from the center of the earth.
So objects entering does not have constant acceleration. Its acceleration is inversely proportional to the square of its distance from the center of the earth. The closer it is, the greater is its acceleration. Of course we should expect this this since as it gets nearer the earth its weight (force of attraction of the earth) also becomes bigger.
Here's a little desert. We know that acceleration on the earth's surface is approximately 9.8 m/s^2. The radius of the earth is approximately 6,378,000 m. Check if the acceleration due to gravity we ordinarily use is correct.
2006-06-08 02:20:44
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answer #2
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answered by dax 3
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9.8 meters per second per second... what that means is for every second you fall, you are going 9.8 meters (32.2 feet) per second faster than you were a second ago. It would not take long to reach tremendous speeds, were it not for air resistance and 'terminal velocity'.
2006-06-08 04:10:13
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answer #3
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answered by eggman 7
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32 feet per second per second.
2006-06-08 02:07:23
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answer #4
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answered by Anonymous
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i think its 16 feet per second per second
2006-06-08 02:06:34
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answer #5
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answered by oldguy 6
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9 metres per second, per second
2006-06-08 04:46:33
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answer #6
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answered by djoldgeezer 7
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this one is easier...
with the acceleration of gravity....
Its value is approx. 9.8m/s....
its called acceleration due to gravity
2006-06-08 02:06:36
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answer #7
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answered by Slang_Guru 1
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120 mph?
2006-06-08 02:05:34
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answer #8
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answered by DS2 3
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