how long would it take abbie if she works alone?
Please include all calculations...Thanks
2006-06-07 16:52:49 · 7 answers · asked by Me 2 in Science & Mathematics ➔ Mathematics
Cathie = 1 unit of work
Abbie = 3 units of work
Beth= 3/2 units of work
So we have that all three add 11/2 units of work.
So if 11/2 units of work require 60 minutes >> then 3 units of work would require:
(11/2*60)/3
330/3
110 minutes
Abbie alone could do the work in 110 minutes
Beth would require 220 minutes (twice as much as Abbie)
Cathie would require 330 minutes (3 times as much as Abbie)
Cynthia
2006-06-07 17:06:55 · answer #1 · answered by Anonymous · 3⤊ 0⤋
How big is the room, and if takes 3 people 60 minutes to paint a room don't hire them get some professionals.
2006-06-11 22:16:40 · answer #2 · answered by retisin2002 4 · 0⤊ 0⤋
a = 2b
a = 3c
a = 2b
b = (a/2)
a = 3c
c = (a/3)
a + b + c = 60
a + (a/2) + (a/3) = 60
Multiply everything by 6
6a + 3a + 2a = 360
11a = 360
a = (360/11)
ANS : about 32.73 minutes or aboue 33 minutes
2006-06-08 09:06:31 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
she takes only 30 min when she work alone
2006-06-08 00:41:20 · answer #4 · answered by Vivek K 1 · 0⤊ 0⤋
1/60 = 1/X + 1/(2X) + 1/(3X)
1/60 = 5.5/(3X)
X = 5.5 * 60 / 3 = 110 minutes
2006-06-08 00:10:38 · answer #5 · answered by none2perdy 4 · 0⤊ 0⤋
Kyn is right.
understand proportionality and inverse-proportionality.
2006-06-08 06:31:17 · answer #6 · answered by K N Swamy 3 · 0⤊ 0⤋
hmmm
2006-06-08 00:15:05 · answer #7 · answered by Albert m 2 · 0⤊ 0⤋