solve and show all work. -3x^2=-36?

Answer 1

-3x^2 = -36
Divide both sides by -3
x^2 = 12
Take the square root of each side.
Remember that when you take the square root, you have to include the positive and negative roots
x = +/- sqrt(12)
x = +/- sqrt(4*3)
x = +/- 2sqrt(3)
x = 2sqrt(3) or -2sqrt(3)

Answer 2

-3x^2=-36
Divide each side by -3:
x^2=12
Take the square root of each side to isolate x. Since I can't find a square root symbol on my computer, the old fashioned exponential notation will have to do. In this case, x^1/2=the square root of x.
(x^2)^1/2=(12)^1/2
x =(12)^1/2
Simplify. Since 3*4=12, and 2^2=4, you can simplify to:
x = 2*(3)^1/2

Answer 3

-3x^2= -36
-3/-3*x^2=-36/-3
x^2=12

Squaroot:12)=x

x=about 3.47 but the exact answer is Squareroot: 12

Answer 4

-3x^2=-36 divide bothsides by -3
x^2=12 take the square root of both sides (sqrt)
x=sqrt12

am I doing your homework?

Answer 5

-3x^2=-36
(-1)(-3x^2)=(-1)(-36)
(3x^2)/3=36/3
x^2=12
x= square root of 12

Answer 6

Minus 3x^2 = -36
Take each side and divide by 3
Gives:
minus x^2 = -12
Multiply both sides by Minus One
Gives
x^2 = 12
Task Square root of both sides
x = plus or minus the square root of 12 (approx 3.464) or approx. negative 3.464 -- either one!

Answer 7

if 4 circumstances x-squared is 36 then divide the two factors by 4 then x-squared = 9 now take the sq. root of the two factors sq. root of x-squared is x sq. root of 9 is 3 so x = 3

Answer 8

the eqn u had give can be solved by complex no only
3x^2=-36
x^2=-12 dividing by 3 thoroughout
x=+or-i sqroot 12
x=+or- 2i sqroot3

Answer 9

3x2=6 3 x1=3

Answer 10

-3x^2=-36
x^2=12
x=sqrt(12)=2 sqrt(3)