Is the answer 6.02 x 10^23
2006-06-07 16:28:54 · 13 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
yes
2006-06-07 16:31:30 · answer #1 · answered by Black Fedora 6 · 0⤊ 1⤋
The molecular weight of CH2O is 30 g and hence 30 g of CH2) is 1 mol substance and will contain a number of molecules equal to the Avagadro's no. which is 6.02*10^23
2006-06-07 22:40:12 · answer #2 · answered by raj 7 · 0⤊ 0⤋
there are 6.023 X 10^23 molecules in a mole.
It happens that the FW of CH2O is 30, so then 30 grams will contain 6.o23 X 10^23 molecules.
2006-06-07 16:33:42 · answer #3 · answered by sanambrosio 3 · 0⤊ 0⤋
first add the atomic mass of each atom.
- in this case C=12 H x 2 = 2 and 0 = 16 final answer 30g
- This is the weight of one MOLE of CH2O
- You are looking for how much is in 30g
-since there is one mole of CH2O and one mole = 6.02 * 10^23 molecules....YOU ARE CORRECT
2006-06-07 16:36:41 · answer #4 · answered by Albert m 2 · 0⤊ 0⤋
It depends on the strength of the gravitational field where you are. On the surface of a brown dwarf it might only take 2000-3000 CH2O molecules to make 30g.
Seriously; I won't do your homework for you.
Show your work and logic so far and you will get HINTS
2006-06-07 16:33:36 · answer #5 · answered by lampoilman 5 · 0⤊ 1⤋
How Many Molecules
2017-01-09 21:20:52 · answer #6 · answered by ketcher 4 · 0⤊ 0⤋
1 mole CH2O is 30.02634g so 30 g of CH2O is less than 1 mole(g/mole) so its less than the Avogadro's number
2006-06-07 19:25:54 · answer #7 · answered by Anonymous · 0⤊ 0⤋
6.022*10^23 molecules
2006-06-07 22:35:21 · answer #8 · answered by Anonymous · 0⤊ 0⤋
formaldehyde - methanal
formula weight = 12.0 + 1.01 + 1.01+ 16.0 = 30.0g/gmol
1.00mol formaldehyde • (6.02 • 10^23 molecules/gmol)
So yes it is.
2006-06-07 16:39:07 · answer #9 · answered by Anonymous · 0⤊ 0⤋
6.04*10^24
2006-06-08 05:17:03 · answer #10 · answered by Anonymous · 0⤊ 0⤋