Here is the end of the question, produced from 20.0g of zinc metal? The book has 29.8g as the answer. Can someone explain how to get that answer?
2006-06-07 07:52:23 · 5 answers · asked by ernie_casarez 4 in Science & Mathematics ➔ Chemistry
I guess you mean how many grams of Zinc Sulphide could be produced
65.4 g of Zn reacts with 32.1g S
To find out how much S 1 g of Zn can react with, divide both numbers by 65,4
1 g of Zn reacts with 32.1/65.4 g S, which is 0,4908 g S
For 20 g Zn, if 1 g Zn reacts with 0,4908g S, 20 g will react with 0,4908*20g = 9.8g S.
The amount of Zinc Sulphide wil therefore be the amount of Zn (20g) plus the amount of Sulphur with which it reacts (9.8g) giving you 29.8g total.
Okay?
2006-06-07 08:05:01 · answer #1 · answered by The_Otter 3 · 0⤊ 0⤋
65.4g of zinc i = 1 gmol of zinc. This reacts with 32.1g of sulphur (= 1 gram mole of sulphur).
Zn + S = ZnS
This would make 1 gram mol of zinc sulphide. (ZnS), (1 gram mol ZnS = 97.5g)
20g of zinc = 20/65.4 = 0.306 gmol of zinc.
This would react with enough sulphur to produce 0.306 gmol of ZnS.
i.e 97.5g X 0.306 = 29.8g. Voila!
To check...the amount of sulphur reacted = 0.306gmol of
sulphur = 0.306 x 32.1 = 9.8g
2006-06-08 01:05:54 · answer #2 · answered by RX-8man 3 · 0⤊ 0⤋
Should you be playing with zinc and sulphur? I know the types of things you can make with that stuff.
2006-06-08 01:44:09 · answer #3 · answered by Anonymous · 0⤊ 0⤋
doesnt make sense....
"how many gram of zinc could be produced by 20.0 gram of zinc metal"
Did u mean zinc sulfide?
2006-06-07 08:14:00 · answer #4 · answered by nickyTheKnight 3 · 0⤊ 0⤋
DO YOUR OWN HOMEWORK!
2006-06-07 09:18:36 · answer #5 · answered by ? 3 · 0⤊ 0⤋