How do you simplify this?

Question

5) squareroot of x^6/4900
6) squareroot of 144x^6
7) squareroot of 25 (a+2)^2

Answer 1

5) find the factors
squareroot of x * x * x * x * x * x / 7*7*5*5*2*2
the factors can come out of the square root by pairs only
you have 3 pairs of x's = x^3
you have 1 pair of 7's so it comes out of the square root as a 7
x^3/7*5*2
x^3/70 is it's simplified term

__________________
if u want all the correct answers then that would tarenirator's answers

Answer 2

You can take the square root of the numerators and denominators seperately.

Looking at the numerator x^6 = x^2 * x^4

sqrt[x^2] = x
sqrt[x^4] = x^2
x* x^2 = x^3

Now do the denominator.

Answer 3

x^6/4900= underrootx^6 /70

144x^6=12*underrootx^6

25(a+2)^2=5(a+2)

Answer 4

5). sqr(x^6/4900)=sqr((x^3)2/(700)^2)=x^3/700
6). sqr(144x^6)=sqr((12X^3)^2) = 12X^3
7). sqr(25(a+2)^2)=sqr((5(a+2))^2)=5(a+2)

Answer 5

sqrt(x^6/4900) =
(sqrt(x^6))/(sqrt(49 * 100)) =
((x^6)^(1/2))/(7 * 10) =
(x^(6 * (1/2)))/70 =
(x^3)/70

--------------------------------------------

sqrt(144x^6) =
sqrt(144) * sqrt(x^6) =
12x^3

----------------------------------------------

sqrt(25(a + 2))^2 =
sqrt(25) * sqrt((a + 2)^2)

The sqrt and ^2 cancel out

5(a + 2) =

5a + 10

Answer 6

(x^3)2/70^2
root of this becomes x^3/70
12^2(x^3)^2
:.12x^3
5^2(a+2)^2
:.5(a+2)