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Divide and simplyfy.
squareroot of 3 divided by squareroot of 3

Add or subtract.
2squareroot of 24 +squareroot of 54

2006-06-06 18:56:57 · 15 answers · asked by rogaciana s 1 in Science & Mathematics Mathematics

15 answers

1

2006-06-06 18:59:38 · answer #1 · answered by cost cutter 3 · 0 0

Previous answer was right. It's one for the reason stated. Answer to second part is 7 times the square root of 6.
First expression breaks down to 4x6. Take the square root of 4, it's 2 and multiply it times the 2 outside of the radical. Follow similar procedure for second expression. Try this with easier numbers to work with to gain understanding. For example square root of 81 equals 9x9. Taking square root of 2 =3, so answer is 3x3 or 9 which is correct. Hope this helps.

2006-06-06 19:06:37 · answer #2 · answered by Superstar 5 · 0 0

SR (3) /SR (3) = 1

any # over itself is 1

The second one, is it 2 times the square root of 24 + square root of 54? If this is the case.

= 4 times sqare root of 6 + 3 times square root of 6
= 7 times square root of 6

2006-06-06 18:58:06 · answer #3 · answered by csucdartgirl 7 · 0 0

#1 sr 3/sr 3=1
#2 sr 24 + sr 54 =24*24+54*54=576+2916=3492

2006-06-06 19:03:22 · answer #4 · answered by sukrantsharma 2 · 0 0

the first answer is of course 1.
the second problem needs a bit of clarification

2006-06-06 19:00:35 · answer #5 · answered by Anonymous · 0 0

sqrt(3)/sqrt(3) = 1 any how u can solve....

2sqrt(24) + sqrt(54) = sqrt(96) + sqrt(54)
= sqrt(6) { sqrt(16)+sqrt(9)}
= sqrt(6) {4+3}
= 7sqrt(6)

2006-06-06 19:03:47 · answer #6 · answered by PRASANNA V 2 · 0 0

1) sr(3)/sr(3)=1
2) sr(24)+sr(54)=2(sr(6)) + 3(sr(6)) = 5(sr(6))
or if you meant 2(sr(24))+sr(54) = 2(2(sr(6))) + 3(sr(6)) = 4(sr(6)) + 3(sr(6)) = 7(sr(6))

2006-06-06 19:04:53 · answer #7 · answered by Cato_I 4 · 0 0

1
7 x SQRT(6)

2006-06-06 19:01:48 · answer #8 · answered by Rambo Smurf 4 · 0 0

1+2(4.898)+7.348 =18.144

2006-06-06 19:12:08 · answer #9 · answered by AboAyman 5 · 0 0

First one is 1
and second one is
17.1
I added

2006-06-06 19:05:36 · answer #10 · answered by Annie R 2 · 0 0

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