solve and express the roots in a +bi form x squared -2x+5=0?

Answer 1

Use the quadratic formula
a = 1, b = -2 and c = 5
[-b +/- sqrt(b^2-4ac)]/(2a)
= [2 +/- sqrt(4-4*1*5)]/(2*1)
= [2 +/- sqrt(4-20)]/2
= [2 +/- sqrt(-16)]/2
= [2 +/- 4i]/2
= (2+4i)/2 or (2-4i)/2
= 1+2i or 1-2i

Answer 2

x^2 - 2x + 5 = 0

x = (-b ± sqrt(b^2 - 4ac))/2a
x = (-(-2) ± sqrt((-2)^2 - 4(1)(5)))/(2(1))
x = (2 ± sqrt(4 - 20))/2
x = (2 ± sqrt(-16))/2
x = (2 ± 4i)/2
x = 1 ± 2i

ANS : 1 + 2i or 1 - 2i