2006-06-06 11:08:59 · 6 answers · asked by pooja 1 in Science & Mathematics ➔ Mathematics
5/(2-3i)
Multiply the top and bottom by the conjugate of the denominator.
The conjugate of 2-3i is 2+3i. You just change the sign in front of the i term
5(2+3i) = 10+15i
(2-3i)(2+3i) = 4 + 9 = 13
Answer: (10+15i)/13
2006-06-06 11:11:37 · answer #1 · answered by MsMath 7 · 1⤊ 0⤋
5/(2-3i) = 5(2+3i)/(2-3i)(2+3i) multiplying Numerator and denominator with the conjugate - as (a+b)(a-b)=a^2-b^2
now the denominator is 2^2-(3i)^2 = 4-3^2.i^2=4-9(-1)=13
numerator is 5(2+3i) = 10+15i
so after rationalization it is (10+15i)/13 or 5(2+3i)/13
2006-06-06 11:24:48 · answer #2 · answered by kalyan_panda 2 · 0⤊ 0⤋
Oops! The answer below was right and I was wrong.
Multiply the fraction by (2 + 3i) / (2 + 3i).
In the numerator, this gives 10 + 15i.
In the denominator, this gives (4 - 6i + 6i - 9i^2) = (4 + 9) = 13.
Simplifying: (10 + 15i) / 13.
2006-06-06 11:11:33 · answer #3 · answered by mattsdx 2 · 0⤊ 0⤋
5/(2 - 3i)
Multiply top and bottom by (2 + 3i)
(5(2 + 3i))/((2 - 3i)(2 + 3i))
(5(2 + 3i)/(4 + 6i - 6i - 9i^2)
(5(2 + 3i))/(4 - 9(-1))
(5(2 + 3i))/(4 + 9)
(5(2 + 3i))/13
ANS : (10 + 15i)/13
2006-06-07 07:44:20 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋
multiply by 2+3i...now go do your own homework!
2006-06-06 11:11:04 · answer #5 · answered by laura 4 · 0⤊ 0⤋
the end of the school year and you still have no idea what this answer is, that is not a good sign.
2006-06-06 11:11:01 · answer #6 · answered by captures_sunsets 7 · 0⤊ 0⤋