chorda ab& cd intersect in circle o at point e if ce=6 ed=5 ad=2 find eb?

Answer 1

You have a theorem leads to :
ce * ed = ae * eb
6 * 5 = ( 2 - eb)*eb
30 = 2 eb - (eb)^2
(eb)^2 - 2 eb + 30 = 0
Which have imaginary roots
if ae = 2 ( not ad as you mentioned )
then 30 = 2*eb
therefor eb = 15