√4x+1+3=0 i am stunned on this one, can you help me.......?

Answer 1

I'm going to guess that you mean for the entire expression (4x+1) to be under the radical sign. (I'm basing that guess purely on what sort of problems I typically see in math textbooks.)

So, start by subtracting the 3 from both sides:

√(4x+1) = -3

Square both sides:

4x+1 = 9

Subtract 1 from both sides:

4x = 8

Divide both sides by 4:

x = 2.

Now, whenever you solve an equation with a square root in it, you've got to test your answers, because you can do everything right and still generate false solutions. And, in fact, that's what happens here:

√(4*2 + 1) + 3 = √9 + 3 = 3 + 3 = 6 which does not equal 0.

That means there are no solutions to this problem, and that's as it should be: since we always assume that a square root is positive, there's no way that we can add √(4x+1), a positive number, to 3, another positive number, and get zero as an answer.

As it happens, if the problem had been

√(4x+1) - 3 = 0,

we would have gotten the exact same answer, x = 2, and it would have worked. But the problem as stated has no solution. (Assuming, that is, that my initial assumption about it was correct.)

Hope that helps!

Answer 2

if by this you mean

sqrt(4x + 1) + 3 = 0
sqrt(4x + 1) = -3
square both sides
4x + 1 = 9
4x = 8
x = 2

Answer 3

(4X)^1/2 + 1 + 3 = 0
(4X)^1/2 = -4
4x = 16
X = 4

Or if you mean :(4^1/2)X +1 +3 = 0
2X = -4
X = -2

Answer 4

x = -sq root 4