can any one can show that 1=0?????

Answer 1

The sum of (-1)^n from 0 to infinite...1-1+1-1+1-1....
Grouping this sum like this first: (1-1)+(1-1)+(1-1)...=0+0+0+...=0
OR Use the following grouping: 1+(-1+1)+(-1+1)+...=1+0+0+0...=1

This is a fun problem, and shows that when using summation, be careful.

Answer 2

Prove: 1 = 0

1. a = b + 1 [*(a-b)
2. (a-b)a = (a-b)(b+1) [expand
3. a^2 - ab = ab + a - b^2 - b [-a
4. a2 - ab -a = ab + a -a - b2 - b[factorise
5. a(a - b - 1) = b(a - b - 1) [/a-b-1
6. a = b [substitute into 1.
7. b + 1 = b [-b
8. Therefore, 1 = 0

of course as a=b+1, a-b-1 = 0 so step 5->6 is invalid, as division by zero is not allowed.

Answer 3

If 1=0 then your system has no solutions.

Answer 4

i can show u


se :-




1 = 0

Answer 5

let say 0!=1! (! means factorial)
so, 0=1

that's all,

Answer 6

no, we cannot show this, without violating the mathematical rules.
we found several questions and answers of this type.
by this time, regular followers would have understood the concept.
You may please go through Basic Math lessons on www.math.com

Answer 7

let us say that
1=study
0=fail
Here it goes
dont study=fail---------(1)
study=dont fail---------(2)
adding (1) n (2)
study+dont study=fail+dont fail
study(1+dont)=fail(1+dont)
study=fail
1=0

Answer 8

As a number or value?

Answer 9

One is a being....Being are nothingness....

One equals nothing....