conditional problem?

Question

http://img64.imageshack.us/my.php?image=problem5fz.jpg

whats the answer ?

i took 1,4,2,3,5,6 as the value of a,b,c,d,x,y

but this did not produce the correct result.

how do i solve ?
how do i choose which adheres the above condition ?

thanks mathgirl.

Answer 1

ax + by > cx + dy
Move the x's to the left side by subtracting cx from each side, and move the y's to the right side by subtracting by from each side
ax - cx > dy - by
Factor x from the left side and y from the right side
x(a-c) > y(d-b)
Now multiply each side by -1 (remember that the inequality sign flips when you multiply each side by a negative number)
x(a-c)(-1)< y(d-b)(-1)
Distribute the negative one through each side
x(-a+c)< y(-d+b)
Now since x -a+c < -d+b
Now rearrange the above equation so that it looks like one of your choices.
Add a to each side and add d to each side.
c+d < a+b or
a+b > c+d
so your answer is choice (3).

Answer 2

i would say a+b>c+d


Update: almost forgot....i'd better mention that i'm a math idiot half the time, so i have no idea if i'm right or not, it's just what i think is right. good luck.