((-5x^(2) - 6) / (x-4)) = ((-15x/x-4)+(6))
2006-06-05 14:04:16 · 5 answers · asked by ikaryuu 1 in Science & Mathematics ➔ Mathematics
((-5x^2-6)/(x-4)) = ((-15x/(x-4))+6)?
bad parenthasis
if that is right the answer is
-5x^2 + 9x + 18 = 0
x = 3 or x = -6/5 (hopefully i did it right)
2006-06-05 14:14:22 · answer #1 · answered by siriasm11 2 · 0⤊ 0⤋
((-5x^(2) - 6) / (x-4)) = ((-15x/x-4)+(6))
-5x^2 - 6 = -15x + 6(x-4) ------ multiplying both sides by (x-4)
0 = 5x^2 -15x + 6x - 24 + 6
5x^2 - 9x - 18 = 0
x = (9 +- 21) / 2(5)
x = 3 or -1.2
2006-06-05 23:41:40 · answer #2 · answered by Kemmy 6 · 0⤊ 0⤋
((-5x^2-6)/x-4)=-15x+6x-24
5x^2-9x+30=0
then solve the rest urself
2006-06-05 22:10:32 · answer #3 · answered by the_saint_heero 3 · 0⤊ 0⤋
............and the answer if you didn't make a parentheses mistake is:
x = 1.3 +- (5.7654i)/2
2006-06-05 21:26:05 · answer #4 · answered by Steve 7 · 0⤊ 0⤋
x={-1.2,3}
2006-06-05 21:13:39 · answer #5 · answered by gradient 2 · 0⤊ 0⤋