The triangle forms a crevice of space in the upper rightcorner once its drawn inside the circle. Find the areas of that region.
2006-06-05 13:05:54 · 7 answers · asked by Persephone 2 in Science & Mathematics ➔ Mathematics
Just the area of that region. I accidently put areas.
2006-06-05 13:08:24 · update #1
The answer is 10.
If you don't believe me, do the problem yourself and compare that with my answer.
2006-06-05 13:07:50 · answer #1 · answered by admoundc 2 · 0⤊ 0⤋
Base same as radius sounds like an equilateral triangle. Area is (1/2)(base)(sin(60°)
=(1/2)(8)4√(3)/2)= 8√(3)
2006-06-05 13:15:21 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Angle = (360 - 60)/ 2 = 150
Area of segment
= (150/360)*pi*8^2 - (1/2)(8)(8)sin150
= 80pi/3 - 16
= 67.78 square units
2006-06-05 16:58:15 · answer #3 · answered by Kemmy 6 · 0⤊ 0⤋
This is where you need that precise mathematical vocabulary; "crevice in space" just doesn't communicate, and circles don't have corners, so what corner are we talking about?
2006-06-05 19:08:44 · answer #4 · answered by Philo 7 · 0⤊ 0⤋
wats a ` a crevice of space in the upper rightcorner ` .
cant u write english ...
2006-06-05 13:09:57 · answer #5 · answered by anand_neo 2 · 0⤊ 0⤋
Yes it's 10.
2006-06-05 13:10:25 · answer #6 · answered by Anonymous · 0⤊ 0⤋
I got 10.32
2006-06-05 13:40:15 · answer #7 · answered by paul b 1 · 0⤊ 0⤋