2006-06-05 12:59:53 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
first x outside x inside x last
(2x*5x) + (2x * -2) + (-5 * 5x) + (-5 * -2)=
10x^2 + -4x + -25x + 10=
10x^2 - 29x + 10
2006-06-05 13:03:57 · answer #1 · answered by fuilui213 6 · 0⤊ 0⤋
If you asking to solve this (2x-5)(5x-2), then the answer is:
10x^2-29x+10
2006-06-05 13:04:19 · answer #2 · answered by bvroeg 2 · 0⤊ 0⤋
10x^2 - 29x +10
2006-06-05 13:02:57 · answer #3 · answered by Anonymous · 0⤊ 0⤋
(2x-5)(5x-2)
= (2x*5x) + (2x*-2) + (-5*5x) + (-5*-2)
= 10x^2 - 4x - 25x + 10
= 10x^2 -29x + 10
2006-06-05 17:07:21 · answer #4 · answered by Kemmy 6 · 0⤊ 0⤋
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2016-11-14 06:36:03 · answer #5 · answered by ? 4 · 0⤊ 0⤋
10x2-29x+10
2006-06-05 13:02:37 · answer #6 · answered by apex 2 · 0⤊ 0⤋