Math Question?

Question

Can anyone factor these?
1) 3x(y - 4) - 2(y - 4)
2) bx + 2x - by - 2y
3) a(x - 3) + c(x - 3)

Please can you help me this assignment is due tomorrow and I had like to do a 22 page packet with like 40 problems on it and I really don't get these 3. The first one to answer them correctly with the work shown will get the best answer.

Answer 1

1) (3xy-12x)-2y+8
cuz 3x times y = 3xy, 3x times -4 = -12x
-2 times y = -2y, -2 times -4 = 8 (-times- = +)
2) second u leave as it is.....
3) ax-3x + cx-3c
cuz atimes x = ax, a times -3 = -3x
cuz c times x = cx and c times -3 = -3c
u should do ur hw on ur own next time though

Answer 2

Simplifying
3x(y + -4) + -2(y + -4) = 0

Reorder the terms:
3x(-4 + y) + -2(y + -4) = 0
(-4 * 3x + y * 3x) + -2(y + -4) = 0
(-12x + 3xy) + -2(y + -4) = 0

Reorder the terms:
-12x + 3xy + -2(-4 + y) = 0
-12x + 3xy + (-4 * -2 + y * -2) = 0
-12x + 3xy + (8 + -2y) = 0

Reorder the terms:
8 + -12x + 3xy + -2y = 0

Solving
8 + -12x + 3xy + -2y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -12x + 3xy + -8 + -2y = 0 + -8

Reorder the terms:
8 + -8 + -12x + 3xy + -2y = 0 + -8

Combine like terms: 8 + -8 = 0
0 + -12x + 3xy + -2y = 0 + -8
-12x + 3xy + -2y = 0 + -8

Combine like terms: 0 + -8 = -8
-12x + 3xy + -2y = -8

Add '2y' to each side of the equation.
-12x + 3xy + -2y + 2y = -8 + 2y

Combine like terms: -2y + 2y = 0
-12x + 3xy + 0 = -8 + 2y
-12x + 3xy = -8 + 2y

Reorder the terms:
8 + -12x + 3xy + -2y = -8 + 2y + 8 + -2y

Reorder the terms:
8 + -12x + 3xy + -2y = -8 + 8 + 2y + -2y

Combine like terms: -8 + 8 = 0
8 + -12x + 3xy + -2y = 0 + 2y + -2y
8 + -12x + 3xy + -2y = 2y + -2y

Combine like terms: 2y + -2y = 0
8 + -12x + 3xy + -2y = 0

The solution to this equation could not be determined.
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Simplifying
bx + 2x + -1by + -2y = 0

Reorder the terms:
bx + -1by + 2x + -2y = 0

Solving
bx + -1by + 2x + -2y = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2x' to each side of the equation.
bx + -1by + 2x + -2x + -2y = 0 + -2x

Combine like terms: 2x + -2x = 0
bx + -1by + 0 + -2y = 0 + -2x
bx + -1by + -2y = 0 + -2x
Remove the zero:
bx + -1by + -2y = -2x

Add '2y' to each side of the equation.
bx + -1by + -2y + 2y = -2x + 2y

Combine like terms: -2y + 2y = 0
bx + -1by + 0 = -2x + 2y
bx + -1by = -2x + 2y

Reorder the terms:
bx + -1by + 2x + -2y = -2x + 2x + 2y + -2y

Combine like terms: -2x + 2x = 0
bx + -1by + 2x + -2y = 0 + 2y + -2y
bx + -1by + 2x + -2y = 2y + -2y

Combine like terms: 2y + -2y = 0
bx + -1by + 2x + -2y = 0

The solution to this equation could not be determined.
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Simplifying
a(x + -3) + c(x + -3) = 0

Reorder the terms:
a(-3 + x) + c(x + -3) = 0
(-3 * a + x * a) + c(x + -3) = 0
(-3a + ax) + c(x + -3) = 0

Reorder the terms:
-3a + ax + c(-3 + x) = 0
-3a + ax + (-3 * c + x * c) = 0
-3a + ax + (-3c + cx) = 0

Solving
-3a + ax + -3c + cx = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '3c' to each side of the equation.
-3a + ax + -3c + 3c + cx = 0 + 3c

Combine like terms: -3c + 3c = 0
-3a + ax + 0 + cx = 0 + 3c
-3a + ax + cx = 0 + 3c
Remove the zero:
-3a + ax + cx = 3c

Add '-1cx' to each side of the equation.
-3a + ax + cx + -1cx = 3c + -1cx

Combine like terms: cx + -1cx = 0
-3a + ax + 0 = 3c + -1cx
-3a + ax = 3c + -1cx

Reorder the terms:
-3a + ax + -3c + cx = 3c + -3c + -1cx + cx

Combine like terms: 3c + -3c = 0
-3a + ax + -3c + cx = 0 + -1cx + cx
-3a + ax + -3c + cx = -1cx + cx

Combine like terms: -1cx + cx = 0
-3a + ax + -3c + cx = 0

Answer 3

you should try to do it yourself. but...

1)3x(y-4)-2(y-4)
each term has (y-4) in common, so you factor it out and are left with

(y-4)(3x-2)


2) the first two terms have x in common, and the last two have y in common, so

x(b+2)-y(b+2)
then factor out b+2 so
(x-y)(b+2)

3)just factor out (x-3) to get
(a+c)(x-3)



these are all factored answers.

Answer 4

For God's sake they are about common factors...So I can do it with my eyes close...I will help you and see how easy they are

Question 1)

The common factor is (y-4) then 3x(y - 4) - 2(y - 4) = (3x-2) (y-4)

Question 2)

Answer 5

For 1 and 3 just distribute and subtract like terms. For 3 just add or subtract like terms.

The start of one would be 3xy -13x (get it)

The start of three would be ax -3a (see its easy)

The start of two would be 2bx^2 (don't fret its simple)

Answer 6

1)3xy-12x-2y-8 so xy(3-4/y-2/x)=8
2)x(b+2)-y(b+2) so (b+2)(x-y)
3)(x-3)(a+c)

Answer 7

whoa im great at math but too bad i m only in 6th grade!! sry!

Answer 8

work it out for yourself you should be ashamed this is just cheating i hope your parents never find out