5!/2!3! x (1/2)^5 = 10/32
The possibilities for 5 children are:
5 boys 5!/5!0! x (1/2)^5 = 1/32
4 boys 5!/4!1! x (1/2)^5 = 5/32
3 boys 5!/3!2! x (1/2)^5 = 10/32
2 boys 5!/2!3! x (1/2)^5 = 10/32
1 boy 5!/1!4! x (1/2)^5 = 5/32
0 boys 5!/0!5! x (1/2)^5 = 1/32
2006-06-05 15:03:44
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answer #1
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answered by rt11guru 6
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You have 5 children with one being a girl or a boy equiprobably (that is, BTW, not the case in Real Life :) )
So you have a number of satisfying cases equal to 10, whille your total number of cases being 2^5=32. The answer is thus 10/32=5/16. Surely not 2/5 or 40% as others say!
2006-06-05 19:39:31
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answer #2
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answered by --sv-- 2
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2/5
2006-06-05 19:27:44
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answer #3
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answered by chick-a-dee 4
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Probability = 5C2 (1/2)^5 = 10/32 = 5/16
2006-06-06 00:13:37
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answer #4
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answered by Kemmy 6
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5/16.
There are 32 possible ways for the 5 children to be born.
2*2*2*2*2 (with each space representing the number of possible outcomes of birth (male or female))
of those 32 possible combinations, 10 contain some combination of 2 boys and 3 girls:
GGBBB
GBGBB
GBBGB
GBBBG
BGGBB
BGBGB
BGBBG
BBGGB
BBGBG
BBBGG
Thus the probability is 10/32 = 5/16
2006-06-05 19:48:07
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answer #5
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answered by David M 2
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ggggg bbbbb
ggggb bbbbg
gggbg bbbgb
ggbgg bbgbb 6/22 or 3/11
gbggg bgbbb
gbbgg bggbb
ggbbg bbggb
gggbb bbbgg
gbbbg bgggb
ggbbb ggbbb
gbbbb bgggg
sorry if it is wrong
2006-06-05 19:48:04
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answer #6
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answered by Melissa♥ 3
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2C5=5!/(2!*3!)=120/(2*6)=10 so probability=0.1.
2006-06-05 19:41:56
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answer #7
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answered by zee_prime 6
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there is no probability for that. it is completely random. however your mathematical equivalent is 40% chance on a girl being born.
2006-06-05 19:29:49
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answer #8
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answered by wizrdofoz2001 2
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what is the probability of WHAT??
2006-06-05 19:32:19
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answer #9
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answered by ½«gumwrapper 5
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