If the moon were twice as far from the earth as it is today, how would the gravitational force it exerts ...?

Question

on the earth compare with the force it exerts today?

Answer 1

The force would be 1/4 what it is now (since gravity follows an inverse-square of distance law). As it is, moon's gravity has next to no effect on our weight on earth, so weight change would be unnoticable. The main effect would be on the tides. Rather than being the primary determinant of tide height, as it is now, the moon would be a secondary influence and the sun would be the primary. This would reduce tidal heights by (very roughly) one half.

Answer 2

The effects would decrease far more than 50%. since F=G((m1)(m2))/r^2. If you double r, then square it, the effect is greatly reduced tides and a moon that is either travelling MUCh slower or will not stay in Earth orbit.

Answer 3

the gravitity force will be less a double. It means, a human's weight is 50 kg, and now he/she can feel only 25 kg

Answer 4

because of the fact this says no longer something with regards to the Earth, it purely talks approximately you and the sunlight. The rigidity of gravity has to do with how close you're to regardless of is attracting you, and because you're dealing with the sunlight at midday, and not on the hours of darkness, you're nearer at midday. So the rigidity is greater at present at midday.

Answer 5

Lessened by about 50%, it would have these effects;

Tides would be lower (less difference between High & Low tides)
Earthquakes would be fewer.
Werewolves would be smaller too.