2006-06-05 11:01:05 · 7 answers · asked by elchucky04k 1 in Science & Mathematics ➔ Mathematics
(3x-3x)/(2x-10+6x-30) = 0
3x-(3x/2x)-10+6x-30
= 3x - (3/2) - 10 + 6x - 30
= 9x - (83/2)
2006-06-05 11:07:39 · answer #1 · answered by MsMath 7 · 0⤊ 0⤋
3x - 3x/2x -10 + 6x - 30
= 3x - 1 1/2 -10 + 6x - 30
= 3x+6x - 1 1/2 - 30
= 9x - 31 1/2
This answer correct because you had no parenthasis .
2006-06-05 11:14:31 · answer #2 · answered by cookiedada 3 · 0⤊ 0⤋
You always have to follow order of operations. Thus, you simplify the 3x/2x first, leaving you with 1x. Your new expression looks like this:
3x-x-10+6x-30
Now, you using the commutative property, you can rewrite the expression like this:
3x-x+6x-10-30
Now, you can simplify the like terms. You get:
8x-40
2006-06-05 11:22:33 · answer #3 · answered by knicksfan12 2 · 0⤊ 0⤋
= 3x - 1.5 -10 + 6x - 30 = 9x - 41.5
Since you didn't put any parentheses
2006-06-05 11:13:50 · answer #4 · answered by a_ebnlhaitham 6 · 0⤊ 0⤋
(3x-3x)/(2x-10+6x-30)=0
3x-(3x/2x)-10+6x-30=8x-40
2006-06-05 11:04:34 · answer #5 · answered by ME! 3 · 0⤊ 0⤋
Sorry, the questions too vague. The brackets could go just about anywhere.
2006-06-05 11:31:31 · answer #6 · answered by brainyandy 6 · 0⤊ 0⤋
zero
where x can't be equal to {5}
2006-06-05 11:10:19 · answer #7 · answered by John T 1 · 0⤊ 0⤋