六份之K-1=2
5+3份之C=4
2份之9D-8=1
列式
2007-10-08 13:51:31 · 9 個解答 · 發問者 ? 6 in 科學 ➔ 數學
k/6-1=2(我唔知你個-1係放係邊,如果放係出面就咁計)
k/6-1+1=2+1
k/6 x 6=3 x 6
k=18
如果放係入面就
k-1/6=2
k-1/6 x 6=2x6
k-1=12
k=13
5+c/3=4(5+唔同c一齊就咁計)
5+c/3-5=4-5
c/3 x 3 = -1x3
c=-3
同c一齊就咁計
(5+c)/3=4
(5+c)/3 x 3=4x3
5+c=12
5+c-5=12-5
c=7
9d/2-8=1
9d/2-8+8=1+8
9d/2 x 2=9x2
9d=18
d=2
2007-10-08 14:02:43 · answer #1 · answered by Hei Wan 2 · 0⤊ 0⤋
k/6-1 =2
=> k-6=12
=> k=18
5+C/3 =4
=> 15+C =12
=> C= -3
9D/2 -8 =1
=> 9D -16 =2
=> 9D = 18
=> D=2
2007-10-08 14:45:16 · answer #2 · answered by heart 2 · 0⤊ 0⤋
1:
K/6-1=2
K/6=3
6X3=18
so,K=18
3:
9D/2-8=1
9D/2=9
9D=18
D=2
2007-10-08 18:03:09 補充：
C/(5 3)=4C/8=42/8=CC=4
2007-10-08 14:01:55 · answer #3 · answered by ShikaP 7 · 0⤊ 0⤋
我唸係
a) k/6 -1 = 2
b) c/(5+3) = 4
c) 9d/2 -8 =1
p.s. -1 同 -8吾係個分母。
2007-10-08 14:00:51 · answer #4 · answered by ? 1 · 0⤊ 0⤋
k-1/6=2
k-1=12
k=13
5+3/c=4
8=4c
c=2
2/9D-8=1
2=9D-8
10=9D
D=10/9
2007-10-08 14:00:46 · answer #5 · answered by ? 3 · 0⤊ 0⤋
1) k/6 - 1 = 2
k/6 = 2 + 1
k = 3 x 6
k = 18
2) 5 + c/3 = 4
c/3 = 4 - 5
c = - 1 x 3
c = - 3
3) 9D/2 - 8 = 1
9D/2 = 1 + 8
9D = 9 x 2
D = 18除9
D = 2
2007-10-08 14:00:25 · answer #6 · answered by Flora 2 · 0⤊ 0⤋
1.6\k-1=2
6\k=3
k=18
2.5+3\c=4
3\c= -1
c= -3
3.2\9d-8=1
2\9d=9
9d=18
d=2
2007-10-08 13:59:20 · answer #7 · answered by natalis_ng 4 · 0⤊ 0⤋
k - 1 / 6 = 2
k - 1 = 12
k = 13
5 + c/3 = 4
c/3 = -1
c = -3
9d -8 /2 = 1
9d = 10
d = 10/9
2007-10-08 13:59:13 · answer #8 · answered by ? 3 · 0⤊ 0⤋
K=12 C=? D=2
2007-10-08 13:58:48 · answer #9 · answered by raymond123 3 · 0⤊ 0⤋