If 6x²-5xy-4y²=0
find
x²+y²/2xy+3y²
Show steps pls.
2007-03-26 14:14:26 · 1 個解答 · 發問者 kawai2006 1 in 科學 ➔ 數學
Simple question,
6x²-5xy-4y²=0
By factorization:
(3x-4y)(2x+y)=0
x=4/3y or x=-1/2y
x²+y²/2xy+3y²
代入x=4/3y
(16/9y²+y²) / (8/3y²+3y²)
=(25/9y²) / (17/3y²)
=25/51
代入x=-1/2y
[(-1/2y)²+y²] / (2*-1/2y*y+3y²)
=5/4y² / 2y²
=5 / 8
Two answers either 25/51 or 5/8
2007-03-26 19:24:38 補充:
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2007-03-28 18:12:39 補充:
我其實想刪除,讓一讓樓上那位,佢答得快,應有鼓勵!
2007-03-26 15:03:10 · answer #1 · answered by 丫發 7 · 0⤊ 0⤋