請問一下 如何化簡此式
［x^4/3 - 2 x^-4/3］ ［x^2/3 - x^-2/3］= ？
2007-03-04 13:49:23 · 4 個解答 · 發問者 東 2 in 科學 ➔ 數學
更正：［x^4/3 - 2 x^-4/3］÷ ［x^2/3 - x^-2/3］= ？
2007-03-04 14:33:32 · update #1
再次更正：［x^4/3 - 2 x^-4/3］÷ ［x^2/3 - x^-2/3］= ？
2007-03-04 18:21:20 · update #2
更正：［x^4/3 - 2 x^-4/3］÷ ［x^2/3 - x^-2/3］= ？
2007-03-04 18:21:46 · update #3
更正：［x^4/3 - 2 x^-4/3］÷ ［x^2/3 - x^-2/3］= ？
2007-03-04 18:22:01 · update #4
更正：［x^4/3 - 2 x^-4/3］÷ ［x^2/3 - x^-2/3］= ？
2007-03-04 18:22:14 · update #5
更正：［x ^ 4/3 - 2 x^- 4/3］÷ ［x ^ 2/3 - x ^ -2/3］= ？
2007-03-04 18:22:41 · update #6
更正：［x^4/3 - 2 加 x^-4/3］÷ ［x^2/3 - x^-2/3］= ？
因為不知道為什麼 (加)打不出來
2007-03-04 18:23:30 · update #7
(x4/3 - 2 ＋ x-4/3) / (x2/3 - x-2/3)
=(x2/3 - x-2/3)2 / (x2/3 - x-2/3)
= x2/3 - x-2/3
如果有問題, 請來函討論. 不然, 我可能會錯失你再補充的疑點.
2007-03-05 07:43:39 · answer #1 · answered by JJ 7 · 0⤊ 0⤋
[ｘ4/3－２＋ｘ-4/3] [ｘ2/3－ｘ-2/3]
＝[(ｘ2/3)2－２*ｘ2/3*ｘ-2/3＋(ｘ-2/3)2] [ｘ2/3－ｘ-2/3]
＝(ｘ2/3－ｘ-2/3)2 (ｘ2/3－ｘ-2/3)
＝ｘ2/3－ｘ-2/3
2007-03-05 17:30:42 補充：
中間空白的地方是＂除＂，奇怪怎麼顯示不出來 ～＂～
2007-03-05 12:30:06 · answer #2 · answered by 郝思緹絲 4 · 0⤊ 0⤋
(X4/3－2X－4/3)/(X2/3－X－2/3)
=［(X4/3－2X－4/3) (X4/3＋X2/3*X－2/3＋X－4/3)］/［(X2/3－X－2/3) (X4/3＋X2/3*X－2/3＋X－4/3)］
=［X8/3＋X4/3－2X－4/3－2X－8/3－1］/［(X2/3)3－(X－2/3)3］
=［X8/3＋X4/3－2X－4/3－2X－8/3－1］/(X2－X－2)...
2007-03-04 17:24:55 · answer #3 · answered by ? 6 · 0⤊ 0⤋
［x^4/3 - 2 x^-4/3］ ［x^2/3 - x^-2/3］
=x^4/3x^2/3 -x^4/3x^-2/3- 2 x^-4/3x^2/3 2 x^-4/3x^-2/3
=x^2-x^2/3-2x^-2/3 x^-2
2007-03-04 14:06:34 · answer #4 · answered by collin 2 · 0⤊ 0⤋