Quick---hand in tomorrow!!!Try your best to answer.
PQRS is a straight line, intersecting two equal circles, centres A and B.
PS is parallel to AB.
Let AM and BN be perpendicular to PS.
Prove that(i)AM=BN(ii)PQ=R S
2007-01-31 16:23:45 · 1 個解答 · 發問者 Anonymous in 科學 ➔ 數學
Emergency!!Quick!!Quick!!!
2007-01-31 16:41:55 · update #1
∠AMQ = 90
∠MAB = 90
∠ABN = 90
∠BNR = 90
AMNB is a rectangle and AM=BN
AM=BN
AQ=BS
∠AMQ = ∠BNS = 90
ΔAMQ=ΔBNS (R.H.S)
therefore MQ=NS
similarly PM=RN
therefore PQ=RS
2007-01-31 16:46:54 · answer #1 · answered by ? 7 · 0⤊ 0⤋