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Question

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In a box of oranges, the number of rotten oranges is 1/19 of the total number of oranges. If 3 more rotten oranges are put into the box, the total number of rotten oranges is 1/10 of the total number of oranges.
(a) Find the original number of rotten oranges in the box.
(b) Find the final number of oranges in the box.

Answer 1

a.let y be the total number of oranges in the box

y/19 + 3 = Y+3 / 10

10y+570=19y+57

y= 57

so the total number of oranges in the box is 57

the original number of rotten oranges in the box= 57乘 1/19
= 3


b the final number of oranges in the box = 57+3 / 10
= 6

2006-11-23 20:32:24 補充：
第2度計錯左-.-係57+3 = 60

Answer 2

let x be the original number of rotten oranges
let the original number of orange = y
the original number of rotten oranges= y/19
the new number of rotten orange = (x+3) =( y+3)/10
x= y/19
y=19x
x+3 = (19x+3)/10
x+3 = (19x+3)/10
10x+30=19x+3
9x=27
x=3
the original number of rotten orange is 3
b the final number of orange
=y+3
=19x+3
=19(3)+3
=57+3
=60
the final number of orange is 60