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1.林先生慣常在早上9時開車取貨,車速100km/hr,需時30min,但有日因修路關係,車速跌至80km/hr,請計算出佢要提早幾多min開車至可以到倉拿貨

2.某手機來價2850元,如果以75折出售仍然可擭利10%,該手機的標價是幾多?

不勝感激

2006-11-07 11:13:53 · 6 個解答 · 發問者 Anonymous in 科學 數學

6 個解答

1.林先生慣常在早上9時開車取貨,車速100km/hr,需時30min,但有日因修路關係,車速跌至80km/hr,請計算佢要提早幾多min出開車至可以到倉拿貨?
林先生平日去到倉的時間:9時+30min=9時30分
去倉的距離:100km/hr乘(30min除2)=100km乘0.5=50km
因修路關係,去倉的時間:50km除80km/hr=37.5min
37.5min-30min=7.5min
所以,佢要提早7.5min出開車至可以到倉拿貨。

2.某手機來價2850元,如果以75折出售仍然可擭利10%,該手機的標價是幾多?
要獲利10%所需的標偵:2850乘(1+10%)=3135元
要以75折出售所需的標價:3135除(75%)=4180元
所以,該手機的標價是4180元。

2006-11-07 11:28:56 · answer #1 · answered by ? 4 · 0 0

Q1:
路程=100/2=50km,平時行半個鐘行0左50km
80km/hr 行 50km 要幾多時間? 50/80*60=37.5min
因此要提早7分30秒出發

Q2:
2850來價想獲利10%要賣2850*1.1=3135元
標價的75折是3135元那標價就是3135/0.75=4180元

2006-11-07 11:50:37 · answer #2 · answered by NCP 2 · 0 0

1. total distance = 100 x 0.5
= 50 km
time required at 80 km/hr = 50/80
= 0.625 hr
= 37.5 min
he need 7.5 min early start to drive to the godown

2. 10% profit on $2,850 = $3,135
selling at 75% on mark price = $3,135/0.75
= $4,180

2006-11-07 11:43:46 · answer #3 · answered by Ping Wah 5 · 0 0

1 早7分30秒
2 擭利成本的10% 4180
擭利售價[的10% 4384.6

2006-11-07 11:28:39 · answer #4 · answered by wing 2 · 0 0

2.  2850 x 75% = X x (100+10%)

2006-11-07 16:32:59 補充:
1. 100 x 30 / 80 - 30

2006-11-07 16:43:59 補充:
2. X x 75% = 2850 x (100 10%)

2006-11-07 11:26:43 · answer #5 · answered by mcjo666 7 · 0 0

1. 7.5min

2. $4180

2006-11-07 11:26:17 · answer #6 · answered by loo 2 · 0 0

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