mp-12nr-8nq+2mq+3mr-4np
=(mp+2mq+3mr)-(12nr-8nq-4np)
=m(p+2q+3r)-4n(3r-2q-p)
=????????
使唔使轉符號呀???
2006-11-06 07:02:50 · 5 個解答 · 發問者 ? 1 in 科學 ➔ 數學
mp-12nr-8nq+2mq+3mr-4np
=p(m-4n)+2q(m-4n)+3r(m-4n)
=(p+2q+3r)(m-4n)
2006-11-06 07:07:36 · answer #1 · answered by ? 6 · 0⤊ 0⤋
第二行寫錯正負號
mp - 12nr - 8nq + 2mq + 3mr - 4np
= ( mp + 2mq + 3mr ) - ( 12nr - 8nq - 4np )
應該是這樣
mp - 12nr - 8nq + 2mq + 3mr - 4np
= ( mp + 2mq + 3mr ) + ( - 12nr - 8nq - 4np ) 先group埋一起
= ( mp + 2mq + 3mr ) - ( 12nr + 8nq + 4np ) 然後再抽正負號才對
= m ( p + 2q + 3r ) - 4n ( 3r + 2q + p )
= ( m - 4n ) ( 3r + 2q + p )
2006-11-06 08:09:45 · answer #2 · answered by 肥 紀 3 · 0⤊ 0⤋
(mp + 2mq + 3mr) - (4np - 8nq - 12nr)
= m(p + 2q + 3r) - 4n(p + 2q + 3r)
= (m - 4n)(p + 2q + 3r)
2006-11-06 07:15:02 · answer #3 · answered by Ping Wah 5 · 0⤊ 0⤋
mp-12nr-8nq+2mq+3mr-4np
=mp+2mq+3mr-12nr-8nq-4np
=m(p+2q+3r)-4n(3r+2q+p)
=m(p+2q+3r)-4n(p+2q+3r)
=(m-4n)(p+2q+3r)
你之所以計算到,是因為你在起初計算時出現了少少錯誤
2006-11-06 07:15:01 · answer #4 · answered by florence 2 · 0⤊ 0⤋
mp-12nr-8nq+2mq+3mr-4np
=-4n(3r+2q+p)+m(3r+2q+p)
=(m-4n)(3r+2q+p)
2006-11-06 07:10:14 · answer #5 · answered by p 6 · 0⤊ 0⤋