1..若, (a b):(b c):(a c) = 4:5:7則a:b:c = ?2..承上題,(a2 b2):(b2 c2)=?ps我要做法喔!!
2006-01-06 13:12:36 · 4 個解答 · 發問者 欣瑜 5 in 科學 ➔ 數學
請各位大大來幫窩選出作家解答ㄅ!!
2006-01-08 12:34:31 · update #1
先交叉相乘...
推出 4ac=5bc=7ab
得到 4ac=7ab(a互消) =>4a=7b =>a:b=7:4
又
4ac=5bc(c互消)=>4a=5b =>a:b=5:4
兩式一起比
a : b: c
5 : 4
7 : 4
_____
35 : 28 : 20
=>a:b:c=35:28:20
第二題:
假設 a=35
b=28
c=20
=> a2 =1225
b2=784
c2=400
(a2 b2):(b2 c2)=1225*784:784*400=(約分)49:16
2006-01-06 13:26:42 · answer #1 · answered by Sean 2 · 0⤊ 0⤋
1.若 (a+b):(b+c):(a+c)=4:5:7
則 a:b:c=?
設 a+b=4r……①
b+c=5r……②
a+c=7r……③
①+②+③ 2(a+b+c)=16r
a+b+c=8r
①→ 4r+c=8r
c=4r
②→ a+5r=8r
a=3r
③→ 7r+b=8r
b=r
→ a:b:c=3r:r:4r
=3:1:4 #
因為與前面部分回答不同,故在此作驗算
【答案】 a:b:c=3:1:4
原式 (a+b):(b+c):(a+c)=4:5:7
令 a=3q
b=q
c=4q
(3q+q):(q+4q):(3q+7q)=4q:5q:7q
=4:5:7 #
【滿足題幹條件】
2.承上題,(a^2+b^2):(b^2+c^2)=?
∵ a=3r b=r c=4r
∴ (a^2+b^2):(b^2+c^2)
=(9r^2+r^2):(r^2+16r^2)
=10r^2:17r^2
=10:17 #
2006-01-06 14:18:28 · answer #2 · answered by Cy-zion 3 · 0⤊ 0⤋
1.
(ab):(bc)=4:5 → 4bc=5ab → c=5a/4
(bc):(ac)=5:7 → 5ac=7bc → b=5a/7
故a:b:c =a:5a/7:5a/4=28:20:35
2.
((a^2)( b^2)):((b^2)( c^2))=(a^2):( c^2)=(a^2):((25(a^2))/16)=16:25
2006-01-06 13:31:44 · answer #3 · answered by ? 5 · 0⤊ 0⤋
令 (a+b):(b+c):(a+c) = 4:5:7 = r,所以a+b = 4r b+c = 5r a+c = 7r故 a = 3r, b = r, c = 4ra:b:c = 3:1:4(a2+b2):(b2+c2) = (9r2+r2):(r2+16r2) = 10:17
2006-01-06 13:27:12 · answer #4 · answered by Frank 7 · 0⤊ 0⤋