一元一次式-------要有算試唷!!
1.(1)化簡6x-{2x 4[3x-2(5x 3)-5]}(2)承(1),若x=負16分之5,求(1)題的值
2005-12-25 05:26:16 · 3 個解答 · 發問者 ? 2 in 科學 ➔ 數學
原式 = 6x-{2x+4[3x-2(5x+3)-5]} = 6x-{2x+4[3x-10x-6-5]} = 6x-{2x+4[-7x -11]} = 6x-{2x-28x-44} = 6x-{-26x-44} = 6x+26x+44 = 32x+44若 x = - 5/16 則原式 = 32*(-5/16)+44 = -10+44 = 34
2005-12-25 06:02:16 · answer #1 · answered by Frank 7 · 0⤊ 0⤋
1. 化簡6x-{2x 4[3x-2(5x 3)-5]}
= 6x-{2x+4[3x-2(5x+3)-5]}
= 6x-{2x+4[3x-10x-6-5]}
= 6x-{2x+4[-7x -11]}
= 6x-{2x-28x-44}
= 6x-{-26x-44}
= 6x+26x+44
= 32x+44
2.承(1),若x=負16分之5,求(1)題的值
x = - 5/16 則
原式 = 32*(-5/16)+44
= -10+44
= 34
2005-12-25 06:45:33 · answer #2 · answered by no_nickname 3 · 0⤊ 0⤋
6x-{2x+4[3x-2(5x+3)-5]}
=6x-{2x+4[3x-10x-6-5]}
=6x-{2x+12x-40x-24-20}
=6x-2x-12x+40x+24+20
=32x+44
若x=-5/16
則
原式=32*(-5/16)+44
=-10+44
=34
2005-12-25 05:46:05 · answer #3 · answered by ssspppyyykimo 5 · 0⤊ 0⤋