解出以下兩個一元多次方程式的解！急.......

Question

解x(x-1)(x-2)=x(x 2)(x-2)解5x(x 1)(x 2)(x 3)=3x(x 1)(x 3)(x-5)

Answer 1

解x(x-1)(x-2)=x(x+2)(x-2)      x(x-1)(x-2)-x(x+2)(x-2)=0     => x(x-2)[(x-1)-(x+2)]=0     => -3x(x-2)=0     => x=0,22. 解5x(x+1)(x+2)(x+3)=3x(x+1)(x+3)(x-5)  => 5x(x+1)(x+2)(x+3)-3x(x+1)(x+3)(x-5)=0  => x(x+1)(x+3)[5(x+2)-3(x-5)]=0  => x(x+1)(x+3)(2x+25)=0  => x=0,-1,-3,-25/2

Answer 2

1.
x(x-1)(x-2)=x(x+2)(x-2)
=>x(x^2-2x-x+2)=x(x^2-2x+2x-4)
=>x(x^2-3x+2)=x(x^2-4)
=>x^3-3x^2+2x-x^3+4x=0
=>-3x^2+6x=0
=>x(-3x+6)=0
=>x=0,(-6/-3)=2

2.
5x(x+1)(x+2)(x+3)=3x(x+1)(x+3)(x-5)
同除以(x+1)(x+3)=>5x(x+2)=3x(x-5)
=>5x^2+10x=3x^2-15x
=>5x^2+10x-3x^2-15x=0
=>2x^2+25x=0
=>x(2x+25)=0
=>x=0,(25/-2)=-12.5