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計算 1234567890/[(1234567891)2 - 1234567890 x 1234567892]

2005-11-21 14:20:42 · 3 個解答 · 發問者 Frank 7 in 科學 數學

3 個解答

看到分母的聯想
(x-a)(x+a)=(x^2)-(a^2)

故原式為
1234567890/[(1234567891)^2-1234567890*1234567892]
=1234567890/[1234567891^2-(1234567891-1)*(1234567891+1)]
=1234567890/{1234567891^2-[(1234567891^2)-(1^2)]}
=1234567890/1
=1234567890

答1234567890

2005-11-21 14:35:04 · answer #1 · answered by ? 5 · 0 0

設1234567890為a
所以a/[(a+1)^2-a*(a+2)]
--> a/(a^2+2a+1-a^2-2a)
-->a/1
=1234567890

2005-11-21 14:35:41 · answer #2 · answered by 小寶 2 · 0 0

設1234567890=Y
原式=Y/[(Y+1)(Y+1)-Y*(Y+2)]
=Y/ (Y*Y+2Y+1)(Y*Y+2Y)
=Y/1
=Y
=1234567890

2005-11-23 01:19:23 補充:
我覺得設X的會比較快說~~
比較複雜的題目也比較不會算錯@@
~"~.....

2005-11-21 14:35:18 · answer #3 · answered by 小朋友 1 · 0 0

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