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化簡 2√3/(2√2-√3+√11)化簡 2√3/(2√2-√3+√11)

2005-11-16 18:31:34 · 3 個解答 · 發問者 Frank 7 in 科學 數學

3 個解答

2√3/(2√2-√3+√11)*(2√2-√3-√11)/(2√2-√3-√11)
=-2√3(2√2-√3-√11)/(4√6)
=-(4-√6-√22)/4

2005-11-17 07:57:25 補充:
yes, he/she did it wrong a bite.

2005-11-17 10:32:47 補充:
Since this problem is too easy, I personally allow you to withdraw this question... I am OK for no point... YES, plz...

2005-11-16 18:59:47 · answer #1 · answered by ? 3 · 0 0

to Joe:
(√8-√3)^2 = 8+3- 16√3
這裡你好像把√8誤算為8了~

2005-11-16 19:56:27 · answer #2 · answered by ? 3 · 0 0

答案等於(√11+√3-2√2)/8
原式
=2√3[(√8-√3)-√11]/[(√8-√3)+√11][(√8-√3)-√11]
=2√3(√8-√3-√11)/(√8-√3)^2-(√11)^2
=(4√6-6-2√33)/(8+3-16√3-11)
=(4√2-2√3-2√11)/(-16)
=(√11+√3-2√2)/8

因為沒點數了,這題也還不難所以就解給你嘍^_^

2005-11-16 18:50:53 · answer #3 · answered by Anonymous · 0 0

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