利用分組,因式分解下列各式
Q1:
(x-1)^2+3x-3
Q2:
(ax-bx)^2-(a-b)x^3
Q3:
a^2b(x^2-xy)+ab^2(y^2-xy)
2005-11-14 17:53:36 · 1 個解答 · 發問者 TEDDY 2 in 科學 ➔ 數學
Q1:(x-1)2+3x-3=(x-1)2+3(x-1)=(x-1)(x-1+3)=(x-1)(x+2)Q2:(ax-bx)2-(a-b)x3=x2(a-b)2-(a-b)x3=x2(a-b)(a-b-x)Q3:a2b(x2-xy)+ab2(y2-xy)=(a2b)x(x-y)+(ab2)y(y-x)=(a2b)x(x-y)-(ab2)y(x-y)=ab(x-y)(ax)-ab(x-y)(by)=ab(x-y)(ax-by)
2005-11-14 18:05:45 · answer #1 · answered by ? 7 · 0⤊ 0⤋