c++的sin cos tan cot 比較大小

Question

請比較ｓｉｎ３０　ｃｏｓ４５　ｔａｎ６０　ｃｏｔ２５　大小順序？

請問以上這題要如何用ｃ++　表示出來呢？　

Answer 1

#include
#include

class trigonometric
{
public:
char* title;
float value;
};

using namespace std;

int main()
{
trigonometric arr[4], temp;
float pi = 3.14159;

// 度
arr[0].title = "sin30: "; arr[0].value = sin(30 * (pi/180));
arr[1].title = "cos45: "; arr[1].value = cos(45 * (pi/180));
arr[2].title = "tan60: "; arr[2].value = tan(60 * (pi/180));
arr[3].title = "cot25: "; arr[3].value = 1/tan(25 * (pi/180));

/* 弳度
arr[0].title = "sin30: "; arr[0].value = sin((float)30);
arr[1].title = "cos45: "; arr[1].value = cos((float)45);
arr[2].title = "tan60: "; arr[2].value = tan((float)60);
arr[3].title = "cot25: "; arr[3].value = 1/tan((float)25);
*/
for (int in = 0; in < 4; in++)
cout << arr[in].title << arr[in].value << endl;

for(int i = 1; i <= 3; i++)
{
for(int j = 0; j < 4-i; j++)
{
if(arr[j].value < arr[j+1].value)
{
temp = arr[j];
arr[j] = arr[j+1];
arr[j+1] = temp;
}
}
}

cout << endl << "大小順序:" << endl;

for (int out = 0; out < 4; out++)
cout << arr[out].title << arr[out].value << endl;

return 0;
}

Answer 2

哇塞！
又是可怕的資料結構，要寫好多的節點程式碼…

＞＿＜！