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FIGURE 2. Mean (<+->SEM) plasma total flavanol concentrations [sum of
plasma ()-epigallocatechin, ()-epicatechin, ()-epigallocatechin-3-
gallate, and ()-epicatechin-3-gallate concentrations] after the consumption
of green tea, black tea, or a green tea extract supplement by 28–30 healthy
subjects.


TABLE 3
Percentage of the total dose of ingested ()-epigallocatechin (EGC), ()-epicatechin (EC), ()-epigallocatechin-3-gallate (EGCG), and ()-epicatechin-
3-gallate (ECG) from green tea (GT), black tea (BT), and a green tea extract supplement (GTS) in plasma and urine1



1 All values are x<+->SEM; n = 28–30 participants in a randomized crossover design. Means in a row with different superscript letters are significantly
different, P < 0.05 (mixed-model ANOVA and Tukey’s method).

2007-04-09 21:46:47 · 1 個解答 · 發問者 Stanley 1 in 科學 化學

X上面有加一槓...我不知道是什麼意思? <+->正負記號
本段出自於Bioavailability and antioxidant activity of tea flavanols after
consumption of green tea, black tea, or a green tea extract
supplement1報告裡

2007-04-09 21:47:57 · update #1

1 個解答

FIGURE 2. Mean (±SEM) plasma total flavanol concentrations [sum of plasma (–)-epigallocatechin, (–)-epicatechin, (–)-epigallocatechin-3-gallate, and (–)-epicatechin-3-gallate concentrations] after the consumption of green tea, black tea, or a green tea extract supplement by 28–30 healthy subjects.
圖2﹕
28-30個健康的受試者服用GT﹑BT或GTS後﹐血液中的平均(包含平均標準誤差SEM)總黃烷醇濃度[EGC﹑EC﹑EGCG及ECG四者之和]

TABLE 3 Percentage of the total dose of ingested (–)-epigallocatechin (EGC), (–)-epicatechin (EC), (–)-epigallocatechin-3-gallate (EGCG), and (–)-epicatechin-3-gallate (ECG) from green tea (GT), black tea (BT), and a green tea extract supplement (GTS) in plasma and urine1
表3﹕
分別進入血液與尿液中的EGC﹑EC﹑EGCG及ECG濃度各佔攝取量(分別來自GT﹑BT﹑GTS)的百分比。

All values are x<+->SEM;
所有數值均以平均值(Xbar)±å¹³å‡æ¨™æº–å·®(SEM=Standard Error of Mean)來表示﹔
n = 28–30 participants in a randomized crossover design.
樣本數=28-30人受到隨機交叉試驗設計

Means in a row with different superscript letters are significantly different, P < 0.05 (mixed-model ANOVA and Tukey’s method).

2007-04-11 07:45:49 · answer #1 · answered by november_kimo 7 · 0 0

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