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Use equations to explain the observation
1.when a few drops of copper(II) sulphate solution are added to the reagent in bottles dliute sodium hydroxide solution or duilte sulphuric acid, a pale blue precipitate forms.

2. When carbon dioxide is pass through the reagent in dilute sulphuric acid, a white precipitate forms.

THX~

2007-03-17 13:04:51 · 2 個解答 · 發問者 mandy 1 in 科學 化學

2 個解答

1. When copper(II) sulphate solution is added to sodium hydroxide solution, a blue precipitate is formed.
Cu^2+(aq) + 2OH^-(aq) → Cu(OH)2(s)

When copper(II) sulphate solution is added to dilute sulphuric acid, there is NO REACTION.

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2. When carbon dioxide is passed through dilute sulphuric acid, ther is NO REACTION.

2007-03-19 01:38:02 補充:
產生藍色沉澱的 full equation :CuSO4(aq) 2NaOH(aq) → Cu(OH)2(s) Na2SO4(aq)

2007-03-19 01:40:07 補充:
唔好人地話有反應,你就作條 equation。HCO3 根本就冇呢樣野,SO3 遇水有劇烈反應,亂作 equation。

2007-03-18 21:36:27 · answer #1 · answered by 老爺子 7 · 0 0

1.
CuSO4+ 2NaOH ---> Cu(OH)2(s)+ Na2SO4

2.
2CO2+ 2H2SO4(aq.) ---> 2HCO3 + 2SO3

2007-03-17 20:32:54 · answer #2 · answered by hilda 2 · 0 0

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