問一個很基本的解方程式題目
30=180/3.3(logx-log10)
解X
請把移項過程講述一下(尤其是log部分)謝謝!
2007-02-13 04:49:10 · 2 個解答 · 發問者 噓噓樂 2 in 教育與參考 ➔ 考試
30=180/3.3(logx-log10)
1=6/3.3(logx-log10)
11(logx-log10)=20
log(x/10)=20/11
x/10=1020/11
x=10*1020/11
x=10(1+20/11)
x=1031/11
2007-02-13 05:03:14 · answer #1 · answered by kinsda 7 · 0⤊ 0⤋
30=180/3.3*(logx-log10)
log x - 1 = 30*3.3/180 (log 10 = 1)
= 11/20
log x = 31/20
x = 1031/20
如果有問題, 請來函討論. 不然, 我可能會錯失你再補充的疑點.
2007-02-13 09:58:27 · answer #2 · answered by JJ 7 · 0⤊ 0⤋