一題物理學題,數據請自設

Question

把氣壓計從大樓落下,用秒錶記下它落下的時間,落後用落下的距離等於重力加速度乘下落時間的平方的一半算出建築物的高度。


其中的所有數據請自設

Answer 1

using the eqution of motion, with initial velocity = 0 m/s, we have
s = (1/2).g.t^2
where s is the height of the building, g is the acceleration due to gravity and t is the time taken.

Taking g=9.81 m/s2,
s = 4.905.t^2

hence measuring the time enables the height of the building to be found.

Answer 2

By s=ut+(1/2)at^2
u=0
a=10m/s^2
LET T=10

height of the building=distance travelled=1/2(10)10^2=500m

assume there is no air resistance