Bom, tem uma regrinha p se calcular derivada desse tipo!
Seja x^a, onde a é um número qualquer....a derivada de x^a será:
a . x^(a-1) (onde ^ é a simbologia p mostrar que está elevado)
Exemplo:
f(x)=x^2
f(x)`=2x
f(x)=4x^5
f(x)`=4.5.x^(5-1)=20x^4 (onde f(x)` representa a derivada)
Agora p resolver a derivada da sua função:
f(x)=3x^2+3x
f(x)`=2.3.x^(2-1) + 1.3.x^(1-1)=6x + 3
2007-02-07 21:58:37
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answer #1
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answered by Lilica 3
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Regra do tombo
f ( x )= 3x^2 + 3x
f ' ( x ) = 2.3x^1 + 1.3.x^0
f ' ( x ) = 6 x + 3
2007-02-07 10:30:18
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answer #2
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answered by Anonymous
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f´(x) = 6x +3.
2007-02-07 09:59:58
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answer #3
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answered by Anonymous
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6x+3
2007-02-08 11:04:05
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answer #4
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answered by log_150 1
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É f'(x) = 6x + 3
2007-02-08 02:10:44
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answer #5
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answered by Steiner 7
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6x+3
2007-02-08 01:17:24
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answer #6
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answered by ricardo 2
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Simples:
2*3x + 3 = 6x + 3
2007-02-07 15:09:55
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answer #7
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answered by Belphegore 5
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f( x ) = 3x² + 3x
f'( x ) = 6x + 3
2007-02-07 10:29:54
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answer #8
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answered by Luiz S 7
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Sim.
6x+3
2007-02-07 10:00:16
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answer #9
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answered by EU 5
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a derivada : 6x + 6
a integral : x^3 + 3/2 x^2
2007-02-07 11:18:25
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answer #10
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answered by Anonymous
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