C 求助[緊急，請於2點半前給]

Question

He is an honest, friendly and hard-working student.
(a)將其存於一個字元陣列(char array)或字串(string, pointer to char)中，並利用循環語句，移動指標(pointer)找出逗點 “,” 的位置並輸出，如本例是在第16個字母位置，應輸出16。若輸入句中有一個以上之逗點，則所有位置一併輸出；若無逗點，則輸出 “NOT FOUND”。
(b)將其各個word(空白space所分開之字串)存於一個指標陣列(pointer array)中，再將其排序(sort)後列印出，如本例由小到大排序應輸出：
He an and friendly hard-working honest, is student.

Answer 1

先給
#include
#include

main()
{
int i, j, k, a;
char ch, buf[80], *(ptr[80]);

printf("請輸入句子 (80字以內) => ");
gets(buf);

k=0; j = -1;
for (i=0;i {
if (buf[i] == ',')
printf(", is in %d\n", i+1);
if (buf[i] == ' ')
{
a = i - j;
ptr[k] = malloc(a);
strncpy(ptr[k], &(buf[j+1]), a-1);
k++;
j = i;
}
}
a = i - j;
ptr[k] = malloc(a);
strncpy(ptr[k], &(buf[j+1]), a-1);
k++;

for (i=0;i {
for (j=i+1;j if (strcmp(ptr[i], ptr[j]) > 0)
{
a=ptr[i];
ptr[i]=ptr[j];
ptr[j]=a;
}
}
for (i=0;i printf("%s\n", ptr[i]);
}