How many moles of ions are there in 1.19g of sodium sulphate (Na2so4) ?
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2006-12-20 15:25:42 · 1 個解答 · 發問者 kingdom_just 4 in 科學 ➔ 化學
Molar mass of Na2SO4 = 2x23 + 32.1 + 4x16 = 142.1 g mol-1
Mass of Na2SO4 = 1.19 g
No. of moles of Na2SO4 = mass / molar mass = 1.19 / 142.1 = 0.00837 mol
Each mole of Na2SO4 contains 3 moles of ions (2 moles of Na+ and 1 moles of SO42-).
No. of moles of ions = 3 x 0.00837 = 0.0251 mol
2006-12-20 17:02:23 · answer #1 · answered by Uncle Michael 7 · 0⤊ 0⤋