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Metal X forms an oxide. 27.53g of this oxide contains 24.96g of X. What is the mole ratio of X to oxgen in the oxide?

(relative atomic masses : O=16.0, X=207.0)

2006-12-17 13:44:55 · 1 個解答 · 發問者 kwan 6 in 科學 化學

1 個解答

No. of moles = mass / (molar mass)

In 27.53 g of the oxide, mass of O = 27.53 - 24.96 = 2.57 g

Mole ratio X : O
= (24.96/207) : (2:57/16)
= 0.1206 : 0.1606
= 1 : 1.332
= 3 : 4

2006-12-17 13:56:04 · answer #1 · answered by Uncle Michael 7 · 0 0

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