Resolva: 3x/5+3x/20+3x/80+ ... = 100?

0 ⤊

Resolva: 3x/5+3x/20+3x/80+ ... = 100?

2006-12-08 06:37:39 · 6 respostas · perguntado por Anonymous em Ciências e Matemática ➔ Matemática

6 respostas

3x/5+3x/20+3x/80+ ... = 100
(3x/5)*(1+1/4+1/4²+1/4³+....) = 100
3x*(1+1/4+1/4²+1/4³+....) = 500
3x*S = 500

Soma dos termos de uma P.G. com -1 < q < 1:
S = a1 / (1-q)
S = 1 / (1-1/4)
S = 1 / 3/4
S = 4/3

=>
3x*S = 500
3x*(4/3) = 500
4x = 500

x = 125

₢

2006-12-08 07:02:23 · answer #1 · answered by Luiz S 7 · 0⤊ 0⤋

impossível!!! falta algo.

2006-12-08 19:50:59 · answer #2 · answered by brunosbeb 2 · 0⤊ 0⤋

Impossível !
A equação é infinita !

2006-12-08 14:51:09 · answer #3 · answered by Leo 2 · 0⤊ 0⤋

Está faltando algo na equação

2006-12-08 14:48:56 · answer #4 · answered by Anonymous · 0⤊ 0⤋

2006-12-08 14:47:40 · answer #5 · answered by sofia t 3 · 0⤊ 0⤋

q = 0,25
>>

2006-12-08 14:42:35 · answer #6 · answered by aeiou 7 · 0⤊ 0⤋