a)7! b)6!-20
2006-12-04 01:00:19 · 7 respostas · perguntado por Anonymous em Ciências e Matemática ➔ Matemática
a)5040; b)700
2006-12-04 01:07:18 · answer #1 · answered by Anonymous · 0⤊ 0⤋
a) 7!=7*6*5*4*3*2*1=5040
b) 6!-20=6*5*4*3*2*1-20=
=720-20=700
Espero ter ajudado.
2006-12-05 11:54:09 · answer #2 · answered by thunder 2 · 0⤊ 0⤋
a)5040
b)700
2006-12-05 05:16:25 · answer #3 · answered by Joaq23 1 · 0⤊ 0⤋
a)7! 7*6*5*4*3*2*1= 5040
b)6!-20 7*6*5*4*3*2*10 -20 = 2500
2006-12-04 06:22:07 · answer #4 · answered by rebeca_laila 3 · 0⤊ 0⤋
Volta pra quarta série!!! É pro seu bem!!!
2006-12-04 02:58:10 · answer #5 · answered by Anonymous · 1⤊ 1⤋
a)
7! = 7*6*5*4*3*2 = 42*20*6 = 840*6 = 5040
b)
6!-20 = (6*5*4*3*2) - 20 = (30*12*2) - 20 = (360*2) - 20 = 720 -20 = 700
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2006-12-04 01:29:54 · answer #6 · answered by Luiz S 7 · 0⤊ 0⤋
o fatorial 7! se resolve da seguinte forma:
7x6x5x4x3x2x1=5040.
o fatorial 6!-20 se resolve da seguinte maneira:
(6x5x4x3x2x1)-20=720-20=700.
respostas:
(a) 5040
(b) 700
2006-12-04 01:12:25 · answer #7 · answered by Anonymous · 0⤊ 0⤋