calcule a soma dos quinze primeiros termos da p.a (-14, -10, -6...)?

Answer 1

Diego,

A soma dos n primeiros termos de uma PA é dada por:

S(n) = (n*(a(1) + a(n)))/2.

Então, o primeiro passo é calcular a(n), que é dado pela fórmula do termo geral:

a(n) = a(1) + (n - 1)*r.

A razão da sua PA é r = -10 - (-14) = 4. Portanto:

a(15) = -14 + (15 -1)*4 = -14 + 14*4 = 42.

Tendo a(15) = 42, podemos calcular a soma dos 15 primeiros termos.

S(15) = (15*(a(1) + a(15)))/2.
S(15) = 15*(-14 + 42)/2
S(15) = 15*(28)/2 = 15*14

S(15) = 210

Answer 2

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Answer 3

n = 15
a1 = -14
r = -10 - (-14) = -10+14 = 4
Resolvendo:
an = a1 + (n-1)r
an = -14 + (15-1)4
an = -14 + 14.4
an = -14 + 56
an = 42

Sn = (a1 + an).n/2
Sn = (-14 + 42)15/2
Sn = 28.15/2
Sn = 210
Resposta: A soma dos quinze primeiros termos da p.a (-14, -10, -6..) é 210. <>>

Answer 4

210