se s=u(t)=-2t^2+2t+1 e t=v(x)=3x-1, determine:
a.) u(v(x))
b.) v(u(t))
2006-11-22 11:31:48 · 10 respostas · perguntado por L U K E 7 em Ciências e Matemática ➔ Matemática
a)
u(v(x))=u(3x-1) = -2(3x-1)²+2(3x-1)+1
u(v(x))= -2(9x²-6x+1)+6x-2+1
u(v(x))= -18x²+12x-2+6x-2+1
u(v(x))= -18x²+18x-3
b)
v(u(t))=v(-2t²+2t+1) = 3(-2t²+2t+1)-1
v(u(t))= -6t²+6t+3-1
v(u(t))= -6t²+6t+2
₢
2006-11-22 11:51:15 · answer #1 · answered by Luiz S 7 · 1⤊ 0⤋
v(x) = 3x - 1
u(t) = 2t^2 + 2t + 1
a) u(v(x)) = 2(3x - 1)^2 + 2(3x - 1) + 1
= 2(9x^2 - 6x + 1) + 6x - 2 + 1
= 18x^2 -12x + 2 + 6x - 1
= 18x^2 - 6x + 1
b) v(u(t)) = 3(2t^2 + 2t + 1) -1
= 6t^2 + 6t + 3 -1
= 6t^2 + 6t +2
2006-11-22 19:41:56 · answer #2 · answered by T Student 1 · 1⤊ 1⤋
v(x) = 3x - 1
u(t) = 2t^2 + 2t + 1
a) u(v(x)) = 2(3x - 1)^2 + 2(3x - 1) + 1
= 2(9x^2 - 6x + 1) + 6x - 2 + 1
= 18x^2 -12x + 2 + 6x - 1
= 18x^2 - 6x + 1
b) v(u(t)) = 3(2t^2 + 2t + 1) -1
= 6t^2 + 6t + 3 -1
= 6t^2 + 6t +2
Isso chama-se função composta, a regra é vc substituir a incógnita pela função pedida e depois resolver com as regras básicas da matemática
2006-11-23 05:45:04 · answer #3 · answered by Alessandro P 1 · 0⤊ 1⤋
U(Vx)=-2(3x-1)"2+2(3x-1)+1
-6x+2+6x-2+1
1...
V(Ux)=3(-2t"2+2t+1)-1
-6t+6t+3-1
2...
2006-11-22 20:49:43 · answer #4 · answered by Anonymous · 0⤊ 1⤋
Luke-anedota....
2006-11-22 20:36:55 · answer #5 · answered by Arqueiro 6 · 0⤊ 1⤋
Gente esse site ta em grego é??
2006-11-22 20:26:25 · answer #6 · answered by Anonymous · 0⤊ 1⤋
v(x) = 3x - 1
u(t) = 2t^2 + 2t + 1
a) u(v(x)) = 2(3x - 1)^2 + 2(3x - 1) + 1
= 2(9x^2 - 6x + 1) + 6x - 2 + 1
= 18x^2 -12x + 2 + 6x - 1
= 18x^2 - 6x + 1
b) v(u(t)) = 3(2t^2 + 2t + 1) -1
= 6t^2 + 6t + 3 -1
= 6t^2 + 6t +2
QDO A GENTE NÃO SABE,COLA,
PORISSO COLEI DO AMIGO
2006-11-22 19:51:07 · answer #7 · answered by Anonymous · 0⤊ 2⤋
vc ta = político.. prometeu 10 ptos e n deu na pergunta da funçao inversa.. a resposta ta la confere, quem sabe se me der os 10 faço o seu dever... hehehe
2006-11-22 19:41:30 · answer #8 · answered by alx 2 · 0⤊ 2⤋
c) N.D.A.
2006-11-22 19:36:53 · answer #9 · answered by Patricinha 1 · 0⤊ 2⤋
a)u.v.x(uxv)
b)vt.ut(v)
2006-11-22 19:51:36 · answer #10 · answered by Tirso Artesão 5 · 0⤊ 4⤋