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把一筆款項平均分給10個人,但其中2人缺席,於是出席的每個人可多得$30,求該筆款項的總數.

2006-11-16 18:41:08 · 6 個解答 · 發問者 Jason 2 in 教育與參考 小學及中學教育

要式

2006-11-16 18:41:29 · update #1

6 個解答

設x=每個人(10個)所得
故10x=8(x+30)
10x=8x+30
2x=30
x=15
每個人(10個)所得15元
故該筆款項的總數:
15*10=150元

2006-11-16 23:54:49 補充:
對不起!做快了,遺漏了8*30=240故該是:設x=每個人(10個)所得故10x=8(x 30)10x=8x 2402x=240x=120每個人(10個)所得120元故該筆款項的總數:120*10=1200元

2006-11-16 18:49:59 · answer #1 · answered by Ming 7 · 0 0

$1200.00

2006-11-17 06:37:34 · answer #2 · answered by ? 1 · 0 0

所以款項的總數是1200元 !
!!!下次教你!!!

2006-11-16 19:14:47 · answer #3 · answered by ? 2 · 0 0

You should declare two equation,
Equation 1
10 people will get X dollars per each.
8 people will get Y dollars per each
10X = 8Y

Equation 2
出席的每個人可多得$30
Y-X = 30

From equation 1,
10X=8Y
X=0.8Y -- sub it to equation 2

From equation 2
Y-X = 30
Y-0.8Y=30
Y=30/0.2=150

The total amount = 8Y = 8*150 = 1200

2006-11-16 18:59:52 · answer #4 · answered by ? 3 · 0 0

10 - 2 x (30)
------------------- x 10 = 總數
2


240
------ x 10 = 總數
2

120 x 10 = 1200

2006-11-16 18:54:25 · answer #5 · answered by 小刺蛋 4 · 0 0

設該款項的總數為$A

A/(10-2) - A/10 = 30

A/8 - A/10 = 30

A (1/8 - 1/10) = 30

A (1/40) = 30

A = 1200

答: 款項的總數是$1200

2006-11-16 18:50:34 · answer #6 · answered by Cherry 3 · 0 0

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