3X²-X=0
X(3X-1)=0
X=0
OU
3X-1=0
ENTÃO:
3X-1=0
3X=1
X=1/3
X={0 , 1/3}
UM ABRAÇO!!!
.
2006-11-01 02:59:10
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answer #1
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answered by Anonymous
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Baskaras:
-b ± √(b² -4ac)
x = -------------------
2a
No caso:
a = parte numerica do x², o seja 3
b = parte numerica do x, o seja -1
c = parte numerica sem x, o seja 0
x = [1 ± √(1 - 4*3*0)] / 6
x = (1 ± √1) / 6
x = (1 ± 1) / 6
x1 = 2/6 = 1/3
x2 = 0/6 = 0
As soluçoes sao dois: 1/3 e 0
2006-11-01 11:33:02
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answer #2
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answered by Andrea F 3
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sei ñ
2006-11-07 19:30:30
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answer #3
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answered by hanna!!7 1
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0 e um terco
2006-11-07 03:11:36
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answer #4
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answered by Anonymous
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3X²-X=0 ENTAO X(3X-1)=0 DAI PODEMOS DIZER QUE
X=0 OU 3X-1=0
X=1/3 LOGO, S={0, 1/3}
2006-11-05 22:19:05
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answer #5
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answered by Marcio Araujo 2
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3x² - x = 0
x(3x - 1) = 0
x = 0
3x - 1 = 0
x = 1/3
S={0, 1/3}
2006-11-01 18:17:12
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answer #6
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answered by girl_007 2
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3x²-x = 0
x(3x - 1) = 0
x = 0
3x = 1
x = 1/3
Solução = {(0; 1/3)}
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2006-11-01 15:45:55
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answer #7
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answered by aeiou 7
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3x² - x = 0
x (3x - 1) = 0
x' = 0
3x - 1 = 0
x'' = 1/3
2006-11-01 11:45:48
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answer #8
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answered by Gemeas 5
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3x²-x = 0
x*(3x - 1) = 0
ou x = 0
3x - 1 = 0
3x = 1
x = 1/3
ou x = 1/3, anulam a equacao.
resposta: x=0 ou x=1/3
2006-11-01 10:46:21
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answer #9
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answered by Luiz S 7
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3x²-x=0
x(3x-1)=0
x=0
3x-1=0
3x=1
x=1/3
2006-11-01 10:45:25
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answer #10
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answered by Guillermo 1
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