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Todas as categorias

6 respostas

a)
(6x-y)² =
=36x² -12xy+y²
Usei o quadrado da diferença:
(a-b)² =
=a² -2ab+b²
b)(m² + 2n³)² =
= (m²)² +2.2n³.m²+(2n³)²
Usei o quadrado da soma:
(a+b)² =
=a² +2ab+b²
c)(5y-1)² =
=25y² -10y+1
usei o quadrado da diferença

2006-10-29 02:26:26 · answer #1 · answered by Anonymous · 0 0

CÁlculo:(acento no Á)

a) (6x - y)² = 36x² - 12xy² + y²
b) (m² + 2n³)² = m^4+ 4m²n³ + 4n^6
c) (5y -1)² = 25y² - 10y + 1
::

2006-10-29 10:03:45 · answer #2 · answered by aeiou 7 · 1 0

Acho que essa é a lição de casa..

2006-10-29 13:08:43 · answer #3 · answered by Joicedijo 4 · 0 0

a) (6x - y)² = 36x² - 12xy + y²

b) (m² + 2n³)² = m^4 + 4m²n³ + 4n^6

c) (5y - 1)² = 25y² - 10y + 1

2006-10-29 10:39:05 · answer #4 · answered by Luiz S 7 · 0 0

a) 36x²-12xy+y²
b) m elevado a 4ª + 4m²n³+4n elevado a 6ª
c) 25y²-10y+1

2006-10-29 10:07:43 · answer #5 · answered by Fagner Toledo 2 · 0 0

um!

2006-10-29 10:07:17 · answer #6 · answered by pensador atemporal 3 · 0 0

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